1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
|
DISPLAY
The display is split up in to seconds, each with 5 subdivisions
(segments). That's a total of 300 segments per revolution.
If the propeller spins at 2000RPM, that's 33.3 revolutions per second,
or 30ms (30,000μs) per revolution. That means we'll be drawing 10,000
segments per second, which is 100μs per segment. With a clock speed
of 16MHz, this is 1600 cycles per segment, which is plenty.
SCEMATIC NOTES
The diode (D14) across the fan's power connections is there because if
the power across the fan breaks (due to the unreliable nature of the
brushes), the motor in the fan has coils, which act like an inductor
and will produce a back EMF (a huge negative voltage across the power
connections) as the magnetic field collapses. This won't be good for
the Arduino and could cause sparks on the brushes. The diode simply
shorts the negative voltage.
The capacitor (C1) and resistor (R14) are there to smooth the power
supply from the unreliable brushes. The capacitor would discharge
fairly slowly (due to the resistance of the circuit), but will charge
very quickly. Potentially, it will charge so quickly that it'll pull
too much current from the power supply (i.e., short the power supply
and trip it). So the resistor limits this. Unfortunately, the
resistor will also have a potentiometer effect (with the resistance of
the main circuit). 10Ω was chosen as a value due to these rough
workings: Lets say the Arduino circuit takes 500mA. If we aim to lose
1V across the resistor, that's 1V / 0.5A = 2Ω (from V=IR). The 100μF
was a guess (from Dad), but "PCB" Mat suggested something larger, like
2200μF. So we went with 1000μF, which appears to power the board
after power-off for a couple of revolutions. The factors here are
that a capacitor that is only able to hold a small charge won't be
able to maintain a current for a reasonable amount of time when the
power breaks. If it's too large, it will take ages to charge and
effectively short the power (save for the resistor) while it does.
|